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debian/boo
...
debian/bul
| Author | SHA1 | Date | |
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7f6e0ec904 |
18
debian/changelog
vendored
18
debian/changelog
vendored
@@ -1,3 +1,21 @@
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shadow (1:4.8.1-1+deb11u1) bullseye-security; urgency=high
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* Non-maintainer upload by the LTS Security Team.
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* CVE-2023-4641: When asking for a new password, shadow-utils asks the
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password twice. If the password fails on the second attempt,
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shadow-utils fails in cleaning the buffer used to store the first
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entry. This may allow an attacker with enough access to retrieve the
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password from the memory. (Closes: #1051062)
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* CVE-2023-29383: It is possible to inject control characters into
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fields provided to the SUID program chfn (change finger). Although it
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is not possible to exploit this directly (e.g., adding a new user
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fails because \n is in the block list), it is possible to misrepresent
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the /etc/passwd file when viewed. (Closes: #1034482)
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* Add Salsa-CI configuration.
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* Silence lintian error that can't be fixed after freeze.
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-- Sylvain Beucler <beuc@debian.org> Fri, 18 Apr 2025 15:46:55 +0200
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shadow (1:4.8.1-1) unstable; urgency=medium
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* debian/default/useradd: Fix typo DHSELL -> DSHELL (Closes: #897028)
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2
debian/passwd.lintian-overrides
vendored
2
debian/passwd.lintian-overrides
vendored
@@ -4,3 +4,5 @@ passwd: setuid-binary usr/bin/chsh 4755 root/root
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passwd: setgid-binary usr/bin/expiry 2755 root/shadow
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passwd: setuid-binary usr/bin/gpasswd 4755 root/root
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passwd: setuid-binary usr/bin/passwd 4755 root/root
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# Fixed in a0f09c4de7ad35b1a7c64cbe7024c9b7236ad491 but would add a Recommend: during LTS
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passwd: missing-depends-on-sensible-utils sensible-editor usr/sbin/vipw
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83
debian/patches/CVE-2023-29383.patch
vendored
Normal file
83
debian/patches/CVE-2023-29383.patch
vendored
Normal file
@@ -0,0 +1,83 @@
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Origin: https://github.com/shadow-maint/shadow/commit/e5905c4b84d4fb90aefcd96ee618411ebfac663d
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Origin: https://github.com/shadow-maint/shadow/commit/2eaea70111f65b16d55998386e4ceb4273c19eb4
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Reviewed-by: Sylvain Beucler <beuc@debian.org>
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Last-Update: 2025-04-15
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From e5905c4b84d4fb90aefcd96ee618411ebfac663d Mon Sep 17 00:00:00 2001
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From: tomspiderlabs <128755403+tomspiderlabs@users.noreply.github.com>
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Date: Thu, 23 Mar 2023 23:39:38 +0000
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Subject: [PATCH] Added control character check
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Added control character check, returning -1 (to "err") if control characters are present.
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---
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lib/fields.c | 11 +++++++----
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1 file changed, 7 insertions(+), 4 deletions(-)
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From 2eaea70111f65b16d55998386e4ceb4273c19eb4 Mon Sep 17 00:00:00 2001
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From: =?UTF-8?q?Christian=20G=C3=B6ttsche?= <cgzones@googlemail.com>
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Date: Fri, 31 Mar 2023 14:46:50 +0200
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Subject: [PATCH] Overhaul valid_field()
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e5905c4b ("Added control character check") introduced checking for
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control characters but had the logic inverted, so it rejects all
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characters that are not control ones.
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Cast the character to `unsigned char` before passing to the character
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checking functions to avoid UB.
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Use strpbrk(3) for the illegal character test and return early.
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---
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lib/fields.c | 24 ++++++++++--------------
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1 file changed, 10 insertions(+), 14 deletions(-)
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Index: shadow-4.8.1/lib/fields.c
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===================================================================
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--- shadow-4.8.1.orig/lib/fields.c
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+++ shadow-4.8.1/lib/fields.c
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@@ -44,9 +44,9 @@
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*
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* The supplied field is scanned for non-printable and other illegal
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* characters.
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- * + -1 is returned if an illegal character is present.
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- * + 1 is returned if no illegal characters are present, but the field
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- * contains a non-printable character.
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+ * + -1 is returned if an illegal or control character is present.
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+ * + 1 is returned if no illegal or control characters are present,
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+ * but the field contains a non-printable character.
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* + 0 is returned otherwise.
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*/
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int valid_field (const char *field, const char *illegal)
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@@ -60,23 +60,22 @@ int valid_field (const char *field, cons
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/* For each character of field, search if it appears in the list
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* of illegal characters. */
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+ if (illegal && NULL != strpbrk (field, illegal)) {
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+ return -1;
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+ }
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+
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+ /* Search if there are non-printable or control characters */
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for (cp = field; '\0' != *cp; cp++) {
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- if (strchr (illegal, *cp) != NULL) {
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+ unsigned char c = *cp;
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+ if (!isprint (c)) {
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+ err = 1;
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+ }
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+ if (iscntrl (c)) {
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err = -1;
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break;
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}
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}
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- if (0 == err) {
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- /* Search if there are some non-printable characters */
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- for (cp = field; '\0' != *cp; cp++) {
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- if (!isprint (*cp)) {
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- err = 1;
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- break;
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- }
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- }
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- }
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-
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return err;
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}
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143
debian/patches/CVE-2023-4641.patch
vendored
Normal file
143
debian/patches/CVE-2023-4641.patch
vendored
Normal file
@@ -0,0 +1,143 @@
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Origin: https://github.com/shadow-maint/shadow/commit/65c88a43a23c2391dcc90c0abda3e839e9c57904
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Reviewed-by: Sylvain Beucler <beuc@debian.org>
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Last-Update: 2025-04-15
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From 65c88a43a23c2391dcc90c0abda3e839e9c57904 Mon Sep 17 00:00:00 2001
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From: Alejandro Colomar <alx@kernel.org>
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Date: Sat, 10 Jun 2023 16:20:05 +0200
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Subject: [PATCH] gpasswd(1): Fix password leak
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How to trigger this password leak?
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~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
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When gpasswd(1) asks for the new password, it asks twice (as is usual
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for confirming the new password). Each of those 2 password prompts
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uses agetpass() to get the password. If the second agetpass() fails,
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the first password, which has been copied into the 'static' buffer
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'pass' via STRFCPY(), wasn't being zeroed.
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agetpass() is defined in <./libmisc/agetpass.c> (around line 91), and
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can fail for any of the following reasons:
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- malloc(3) or readpassphrase(3) failure.
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These are going to be difficult to trigger. Maybe getting the system
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to the limits of memory utilization at that exact point, so that the
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next malloc(3) gets ENOMEM, and possibly even the OOM is triggered.
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About readpassphrase(3), ENFILE and EINTR seem the only plausible
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ones, and EINTR probably requires privilege or being the same user;
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but I wouldn't discard ENFILE so easily, if a process starts opening
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files.
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- The password is longer than PASS_MAX.
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The is plausible with physical access. However, at that point, a
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keylogger will be a much simpler attack.
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And, the attacker must be able to know when the second password is being
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introduced, which is not going to be easy.
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How to read the password after the leak?
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~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
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Provoking the leak yourself at the right point by entering a very long
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password is easy, and inspecting the process stack at that point should
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be doable. Try to find some consistent patterns.
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Then, search for those patterns in free memory, right after the victim
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leaks their password.
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Once you get the leak, a program should read all the free memory
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searching for patterns that gpasswd(1) leaves nearby the leaked
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password.
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On 6/10/23 03:14, Seth Arnold wrote:
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> An attacker process wouldn't be able to use malloc(3) for this task.
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> There's a handful of tools available for userspace to allocate memory:
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>
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> - brk / sbrk
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> - mmap MAP_ANONYMOUS
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> - mmap /dev/zero
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> - mmap some other file
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> - shm_open
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> - shmget
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>
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> Most of these return only pages of zeros to a process. Using mmap of an
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> existing file, you can get some of the contents of the file demand-loaded
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> into the memory space on the first use.
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>
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> The MAP_UNINITIALIZED flag only works if the kernel was compiled with
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> CONFIG_MMAP_ALLOW_UNINITIALIZED. This is rare.
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>
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> malloc(3) doesn't zero memory, to our collective frustration, but all the
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> garbage in the allocations is from previous allocations in the current
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> process. It isn't leftover from other processes.
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>
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> The avenues available for reading the memory:
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> - /dev/mem and /dev/kmem (requires root, not available with Secure Boot)
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> - /proc/pid/mem (requires ptrace privileges, mediated by YAMA)
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> - ptrace (requires ptrace privileges, mediated by YAMA)
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> - causing memory to be swapped to disk, and then inspecting the swap
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>
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> These all require a certain amount of privileges.
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How to fix it?
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~~~~~~~~~~~~~~
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memzero(), which internally calls explicit_bzero(3), or whatever
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alternative the system provides with a slightly different name, will
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make sure that the buffer is zeroed in memory, and optimizations are not
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allowed to impede this zeroing.
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This is not really 100% effective, since compilers may place copies of
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the string somewhere hidden in the stack. Those copies won't get zeroed
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by explicit_bzero(3). However, that's arguably a compiler bug, since
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compilers should make everything possible to avoid optimizing strings
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that are later passed to explicit_bzero(3). But we all know that
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sometimes it's impossible to have perfect knowledge in the compiler, so
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this is plausible. Nevertheless, there's nothing we can do against such
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issues, except minimizing the time such passwords are stored in plain
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text.
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Security concerns
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~~~~~~~~~~~~~~~~~
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We believe this isn't easy to exploit. Nevertheless, and since the fix
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is trivial, this fix should probably be applied soon, and backported to
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all supported distributions, to prevent someone else having more
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imagination than us to find a way.
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Affected versions
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~~~~~~~~~~~~~~~~~
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All. Bug introduced in shadow 19990709. That's the second commit in
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the git history.
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Fixes: 45c6603cc86c ("[svn-upgrade] Integrating new upstream version, shadow (19990709)")
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Reported-by: Alejandro Colomar <alx@kernel.org>
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Cc: Serge Hallyn <serge@hallyn.com>
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Cc: Iker Pedrosa <ipedrosa@redhat.com>
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Cc: Seth Arnold <seth.arnold@canonical.com>
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Cc: Christian Brauner <christian@brauner.io>
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Cc: Balint Reczey <rbalint@debian.org>
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Cc: Sam James <sam@gentoo.org>
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Cc: David Runge <dvzrv@archlinux.org>
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Cc: Andreas Jaeger <aj@suse.de>
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Cc: <~hallyn/shadow@lists.sr.ht>
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Signed-off-by: Alejandro Colomar <alx@kernel.org>
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---
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src/gpasswd.c | 1 +
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1 file changed, 1 insertion(+)
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Index: shadow-4.8.1/src/gpasswd.c
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===================================================================
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--- shadow-4.8.1.orig/src/gpasswd.c
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+++ shadow-4.8.1/src/gpasswd.c
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@@ -911,6 +911,7 @@ static void change_passwd (struct group
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for (retries = 0; retries < RETRIES; retries++) {
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cp = getpass (_("New Password: "));
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if (NULL == cp) {
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+ memzero (pass, sizeof pass);
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exit (1);
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}
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3
debian/patches/series
vendored
3
debian/patches/series
vendored
@@ -14,3 +14,6 @@
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508_nologin_in_usr_sbin
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505_useradd_recommend_adduser
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501_commonio_group_shadow
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CVE-2023-4641.patch
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CVE-2023-29383.patch
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13
debian/salsa-ci.yml
vendored
Normal file
13
debian/salsa-ci.yml
vendored
Normal file
@@ -0,0 +1,13 @@
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---
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# LTS/ELTS CI
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include:
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- https://salsa.debian.org/lts-team/pipeline/raw/master/recipes/bullseye.yml
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# These didn't work before LTS, not attempting to fix after freeze
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#blhc:
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# allow_failure: true
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# https://salsa.debian.org/salsa-ci-team/pipeline/-/issues/275
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piuparts:
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allow_failure: true
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Reference in New Issue
Block a user