libcamera: Print Timer identifier
The Timer debug output does not report to which timer a condition refers to. Fix that by printing the Timer address. Signed-off-by: Jacopo Mondi <jacopo@jmondi.org> Reviewed-by: Laurent Pinchart <laurent.pinchart@ideasonboard.com>
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@@ -214,7 +214,8 @@ int EventDispatcherPoll::poll(std::vector<struct pollfd> *pollfds)
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timeout = { 0, 0 };
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LOG(Event, Debug)
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<< "timeout " << timeout.tv_sec << "."
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<< "next timer " << nextTimer << " expires in "
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<< timeout.tv_sec << "."
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<< std::setfill('0') << std::setw(9)
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<< timeout.tv_nsec;
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}
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@@ -96,7 +96,7 @@ void Timer::start(std::chrono::milliseconds duration)
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void Timer::start(std::chrono::steady_clock::time_point deadline)
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{
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if (Thread::current() != thread()) {
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LOG(Timer, Error) << "Timer can't be started from another thread";
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LOG(Timer, Error) << "Timer " << this << " << can't be started from another thread";
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return;
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}
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@@ -128,7 +128,7 @@ void Timer::stop()
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return;
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if (Thread::current() != thread()) {
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LOG(Timer, Error) << "Timer can't be stopped from another thread";
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LOG(Timer, Error) << "Timer " << this << " can't be stopped from another thread";
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return;
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}
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