libcamera: base: utils: Simplify operator<< for Duration
There is no real need for a function template. It is not defined in a header file, so it has limited availability, and there exists only a single instantion. So convert it to use `std::ostream` directly, like most `operator<<` in the code base. Signed-off-by: Barnabás Pőcze <barnabas.pocze@ideasonboard.com> Reviewed-by: Kieran Bingham <kieran.bingham@ideasonboard.com> Reviewed-by: Laurent Pinchart <laurent.pinchart@ideasonboard.com>
This commit is contained in:
@@ -424,9 +424,7 @@ scope_exit(EF) -> scope_exit<EF>;
|
||||
} /* namespace utils */
|
||||
|
||||
#ifndef __DOXYGEN__
|
||||
template<class CharT, class Traits>
|
||||
std::basic_ostream<CharT, Traits> &operator<<(std::basic_ostream<CharT, Traits> &os,
|
||||
const utils::Duration &d);
|
||||
std::ostream &operator<<(std::ostream &os, const utils::Duration &d);
|
||||
#endif
|
||||
|
||||
} /* namespace libcamera */
|
||||
|
||||
@@ -658,11 +658,9 @@ void ScopeExitActions::release()
|
||||
} /* namespace utils */
|
||||
|
||||
#ifndef __DOXYGEN__
|
||||
template<class CharT, class Traits>
|
||||
std::basic_ostream<CharT, Traits> &operator<<(std::basic_ostream<CharT, Traits> &os,
|
||||
const utils::Duration &d)
|
||||
std::ostream &operator<<(std::ostream &os, const utils::Duration &d)
|
||||
{
|
||||
std::basic_ostringstream<CharT, Traits> s;
|
||||
std::ostringstream s;
|
||||
|
||||
s.flags(os.flags());
|
||||
s.imbue(os.getloc());
|
||||
@@ -671,11 +669,6 @@ std::basic_ostream<CharT, Traits> &operator<<(std::basic_ostream<CharT, Traits>
|
||||
s << d.get<std::micro>() << "us";
|
||||
return os << s.str();
|
||||
}
|
||||
|
||||
template
|
||||
std::basic_ostream<char, std::char_traits<char>> &
|
||||
operator<< <char, std::char_traits<char>>(std::basic_ostream<char, std::char_traits<char>> &os,
|
||||
const utils::Duration &d);
|
||||
#endif
|
||||
|
||||
} /* namespace libcamera */
|
||||
|
||||
Reference in New Issue
Block a user