Explicitly set parameter name when call SettingsPage.create function
Bug: 244122804 Test: manual - build SettingsGoogle Change-Id: I068857ac3a5e12cfcf0148789b546476663414e1
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@@ -59,7 +59,7 @@ object AppsMainPageProvider : SettingsPageProvider {
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SettingsEntryBuilder.createInject(owner = SettingsPage.create(name)).setIsAllowSearch(false)
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override fun buildEntry(arguments: Bundle?): List<SettingsEntry> {
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val owner = SettingsPage.create(name, parameter, arguments)
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val owner = SettingsPage.create(name, parameter = parameter, arguments = arguments)
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return listOf(
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SpecialAppAccessPageProvider.buildInjectEntry().setLink(fromPage = owner).build(),
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)
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@@ -53,7 +53,7 @@ object SpecialAppAccessPageProvider : SettingsPageProvider {
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SettingsEntryBuilder.createInject(owner = SettingsPage.create(name)).setIsAllowSearch(false)
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override fun buildEntry(arguments: Bundle?): List<SettingsEntry> {
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val owner = SettingsPage.create(name, parameter, arguments)
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val owner = SettingsPage.create(name, parameter = parameter, arguments = arguments)
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return listOf(
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AllFilesAccessAppListProvider,
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DisplayOverOtherAppsAppListProvider,
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@@ -36,7 +36,7 @@ object HomePageProvider : SettingsPageProvider {
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}
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override fun buildEntry(arguments: Bundle?): List<SettingsEntry> {
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val owner = SettingsPage.create(name, parameter, arguments)
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val owner = SettingsPage.create(name, parameter = parameter, arguments = arguments)
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return listOf(
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AppsMainPageProvider.buildInjectEntry().setLink(fromPage = owner).build(),
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)
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