246edc0481
memset(3) returns the input pointer. The assignment was effectively a no-op, and just confused the code. Cc: Christian Göttsche <cgzones@googlemail.com> Cc: Serge Hallyn <serge@hallyn.com> Cc: Iker Pedrosa <ipedrosa@redhat.com> Signed-off-by: Alejandro Colomar <alx@kernel.org>
45 lines
802 B
C
45 lines
802 B
C
/*
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* SPDX-FileCopyrightText: 2022-2023, Christian Göttsche <cgzones@googlemail.com>
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* SPDX-FileCopyrightText: 2023, Alejandro Colomar <alx@kernel.org>
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* SPDX-License-Identifier: BSD-3-Clause
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*/
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#ifndef SHADOW_INCLUDE_LIBMISC_MEMZERO_H_
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#define SHADOW_INCLUDE_LIBMISC_MEMZERO_H_
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#include <config.h>
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#include <stddef.h>
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#include <string.h>
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#include <strings.h>
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inline void memzero(void *ptr, size_t size);
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inline void strzero(char *s);
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inline void
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memzero(void *ptr, size_t size)
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{
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#if defined(HAVE_MEMSET_EXPLICIT)
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memset_explicit(ptr, 0, size);
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#elif defined(HAVE_EXPLICIT_BZERO)
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explicit_bzero(ptr, size);
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#else
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memset(ptr, '\0', size);
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__asm__ __volatile__ ("" : : "r"(ptr) : "memory");
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#endif
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}
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inline void
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strzero(char *s)
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{
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memzero(s, strlen(s));
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}
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#endif // include guard
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