passwd: fall back to non-PAM code when prefix is used

Prefix does not make sense when we use PAM, so when the option
is used behave as if --with-libpam=no was used to configure the
project.

libmisc/Makefile.am

@@ -5,7 +5,13 @@ AM_CPPFLAGS = -I$(top_srcdir)/lib -I$(top_srcdir) $(ECONF_CPPFLAGS)
 
 noinst_LTLIBRARIES = libmisc.la
 
-libmisc_la_CFLAGS = $(LIBBSD_CFLAGS)
+if USE_PAM
+LIBCRYPT_PAM = $(LIBCRYPT)
+else
+LIBCRYPT_PAM =
+endif
+
+libmisc_la_CFLAGS = $(LIBBSD_CFLAGS) $(LIBCRYPT_PAM)
 libmisc_la_SOURCES = \
 	addgrps.c \
 	age.c \

libmisc/obscure.c

@@ -9,8 +9,6 @@
 
 #include <config.h>
 
-#ifndef USE_PAM
-
 #ident "$Id$"
 
 
@@ -247,7 +245,3 @@ bool obscure (const char *old, const char *new, const struct passwd *pwdp)
 	}
 	return true;
 }
-
-#else				/* !USE_PAM */
-extern int ISO_C_forbids_an_empty_translation_unit;
-#endif				/* !USE_PAM */

libmisc/pwd2spwd.c

@@ -11,8 +11,6 @@
 
 #ident "$Id$"
 
-#ifndef USE_PAM
-
 #include <sys/types.h>
 #include "prototypes.h"
 #include "defines.h"
@@ -61,7 +59,4 @@ struct spwd *pwd_to_spwd (const struct passwd *pw)
 
 	return &sp;
 }
-#else				/* USE_PAM */
-extern int ISO_C_forbids_an_empty_translation_unit;
-#endif				/* !USE_PAM */