Rework the de-duplication scheme for shortcuts.
Bug: 4646172 Change-Id: I88966f3e910f51711ce49336fb9134d0953930de
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@@ -90,22 +90,38 @@ public class UserDictionaryAddWordContents {
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/* package */ void apply(final Context context) {
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final ContentResolver resolver = context.getContentResolver();
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if (UserDictionaryAddWordContents.MODE_EDIT == mMode && !TextUtils.isEmpty(mOldWord)) {
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UserDictionarySettings.deleteWord(mOldWord, resolver);
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// Mode edit: remove the old entry.
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UserDictionarySettings.deleteWord(mOldWord, mOldShortcut, resolver);
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}
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final String newWord = mWordEditText.getText().toString();
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final String newShortcut;
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if (null == mShortcutEditText) {
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newShortcut = null;
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} else {
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final String tmpShortcut = mShortcutEditText.getText().toString();
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if (TextUtils.isEmpty(tmpShortcut)) {
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newShortcut = null;
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} else {
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newShortcut = tmpShortcut;
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}
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}
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if (TextUtils.isEmpty(newWord)) {
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// If the word is somehow empty, don't insert it.
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return;
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}
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// Disallow duplicates.
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// TODO: Redefine the logic when we support shortcuts.
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UserDictionarySettings.deleteWord(newWord, resolver);
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// Disallow duplicates. If the same word with no shortcut is defined, remove it; if
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// the same word with the same shortcut is defined, remove it; but we don't mind if
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// there is the same word with a different, non-empty shortcut.
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UserDictionarySettings.deleteWord(newWord, null, resolver);
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if (!TextUtils.isEmpty(newShortcut)) {
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// If newShortcut is empty we just deleted this, no need to do it again
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UserDictionarySettings.deleteWord(newWord, newShortcut, resolver);
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}
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// In this class we use the empty string to represent 'all locales' and mLocale cannot
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// be null. However the addWord method takes null to mean 'all locales'.
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UserDictionary.Words.addWord(context, newWord.toString(),
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FREQUENCY_FOR_USER_DICTIONARY_ADDS,
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null == mShortcutEditText ? null : mShortcutEditText.getText().toString(),
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FREQUENCY_FOR_USER_DICTIONARY_ADDS, newShortcut,
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TextUtils.isEmpty(mLocale) ? null : Utils.createLocaleFromString(mLocale));
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}
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